djc: > As it is possible that the tuples will not always be the same word in > variant cases > result = sum(r.values(), ()) > will do fine and is as simple as I suspected the answer would be.
It is simple, but I suggest you to take a look at the speed of that part of your code into your program. With this you can see the difference: from time import clock d = dict((i,range(300)) for i in xrange(300)) t = clock() r1 = sum(d.values(), []) print clock() - t t = clock() r2 = [] for v in d.values(): r2.extend(v) print clock() - t assert r1 == r2 Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list
