Tuomas wrote:
> def g(*arg):
> return arg
>
> def f(*arg):
> return g(arg)
>
> How can g know if it is called directly with (('foo', 'bar'),) or via f
> with ('foo', 'bar'). I coud write in f: return g(arg[0], arg[1]) if I
> know the number of arguments, but what if I don't know that in design time?
So it seems that I would like to have an unpack operator:
def f(*arg):
return(!*arg)
TV
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