Diez B. Roggisch wrote:
> Tuomas schrieb:
>
>> >>> def g(*arg):
>> ... return arg
>> ...
>> >>> g('foo', 'bar')
>> ('foo', 'bar')
>> >>> # seems reasonable
>> ...
>> >>> g(g('foo', 'bar'))
>> (('foo', 'bar'),)
>> >>> # not so good, what g should return to get rid of the outer tuple
>
>
> g(*g('foo', 'bar'))
>
>
> * and ** are the symetric - they capture ellipsis arguments, and they
> make iterables/dicts passed as positional/named arguments.
>
> Diez
Thanks Diez
And what about this case if I want the result ('foo', 'bar')
>>> def f(*arg):
... return g(arg)
...
>>> f('foo', 'bar')
(('foo', 'bar'),)
>>> def h(*arg):
... return arg[0]
...
>>> g=h
>>> f('foo', 'bar')
('foo', 'bar')
Where can g know it should use arg[0] when arg is forwarded?
TV
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