Gabriel Genellina <[EMAIL PROTECTED]> writes: > > >>> sorted((x[1], x[0]) for x in enumerate(a)) > >[(1, 7), (2, 4), (2, 8), (3, 2), (4, 1), (5, 3), (6, 5), (7, 6), (9, 0)] > > Why forcing to use enumerate if it doesn't fit? And a generator won't > help here since you have to access all the items. > > sorted([(a[i],i) for i in range(len(a))])
I think sorted((x,i) for i,x in enumerate(a)) looks nicer than the above. -- http://mail.python.org/mailman/listinfo/python-list
