Paul Rubin wrote: > Gabriel Genellina <[EMAIL PROTECTED]> writes: > >>> >>> sorted((x[1], x[0]) for x in enumerate(a)) >>>[(1, 7), (2, 4), (2, 8), (3, 2), (4, 1), (5, 3), (6, 5), (7, 6), (9, 0)] >> >>Why forcing to use enumerate if it doesn't fit? And a generator won't >>help here since you have to access all the items. >> >>sorted([(a[i],i) for i in range(len(a))]) > > > I think > > sorted((x,i) for i,x in enumerate(a)) > > looks nicer than the above.
Indeed it does: an excellent refinement of my rather crappily-expressed original idea. regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://holdenweb.blogspot.com Recent Ramblings http://del.icio.us/steve.holden -- http://mail.python.org/mailman/listinfo/python-list
