Marc 'BlackJack' Rintsch wrote:
> I would spell it:
>
> if strg.endswith('\0'):
> strg = strg[:-1]unless you're in a hurry; startswith and endswith are horribly inefficient compared to ordinary indexing/slicing. (as I've pointed out elsewhere, even "s[:len(t)] == t" is usually faster than "s.startswith(t)" for short prefixes, where "short" is a lot longer than you may think). </F> -- http://mail.python.org/mailman/listinfo/python-list
