Robert,
Thanks to you and everyone else for the help. The "s.split('\x00',
1)[0] " solved the problem.
Thanks again,
MDM
Robert Kern wrote:
> Michael wrote:
> > I guess, I still don't see how this will work. I'm receiving a C
> > zero-terminated string in my Python program as a 1K byte block (UDP
> > datagram). If the string sent was "abc", then what I receive in Python
> > is <a><b><c><0><garbage><garbage>...<last_garbage_byte>. How is Python
> > going to know where in this 1K byte block the end of the string is? It
> > seems that what I need to do is tell Python that the string ends at
> > zero-relative index 3. What am I missing here?
>
> Nothing. This is what I would do:
>
>
> In [34]: s
> Out[34]: 'abc\x00garbage'
>
> In [35]: s.split('\x00', 1)[0]
> Out[35]: 'abc'
>
> In [36]: s.split?
> Type: builtin_function_or_method
> Base Class: <type 'builtin_function_or_method'>
> String Form: <built-in method split of str object at 0x6ada2c8>
> Namespace: Interactive
> Docstring:
> S.split([sep [,maxsplit]]) -> list of strings
>
> Return a list of the words in the string S, using sep as the
> delimiter string. If maxsplit is given, at most maxsplit
> splits are done. If sep is not specified or is None, any
> whitespace string is a separator.
>
>
> Using the maxsplit argument saves split from having to do unnecessary work
> splitting the garbage portion if there are nulls there, too.
>
> --
> Robert Kern
>
> "I have come to believe that the whole world is an enigma, a harmless enigma
> that is made terrible by our own mad attempt to interpret it as though it
> had
> an underlying truth."
> -- Umberto Eco
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