Chris Wright wrote: > 1) I want to iterate over a list "N at a time" > sort of like: > > # Two at a time... won't work, obviously > > >>> for a, b in [1,2,3,4]: > ... print a,b > ...
Try this: l = [1, 2, 3, 4] for a, b in zip(*[iter(l)]*2): print a, b zip(*[iter(seq)]*N) will group by N (but if there are any odd items at the end it will ignore them). map(None, *[iter(seq)]*N) will group by N padding the last item with None if it needs to. -- http://mail.python.org/mailman/listinfo/python-list
