>>> for i in dir():
>>> if eval(i) == Banana:
>>> print i
>> (sound of head hitting desk)
>>
>> </F>
>>
> lol
As freakish as the solution was, it's not too far off from
something that actually works (mostly, kinda sorta):
>>> banana = {}
>>> spatula = banana
>>> propane = {}
>>> [name for name in dir() if id(eval(name)) == id(banana)]
['banana', 'spatula']
>>> dir()
['__builtins__', '__doc__', '__name__', 'banana', 'name',
'propane', 'spatula']
While the original just compared on value (and thus, with the
original "solution", "propane" would also be found), it should be
pretty safe to compare on id() equality.
Okay, it's semi-obcene in my book, but it's an actual solution in
a way.
-tkc
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