Lad wrote: > Sybren Stuvel wrote: > > Lad enlightened us with: > > > How can I find days and minutes difference between two datetime > > > objects? > > > For example If I have > > > b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000) > > > a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000) > > > > diff = b - a > > Ok, I tried > > >>> diff=b-a > >>> diff > datetime.timedelta(0, 52662, 922000) > >>> diff.min > datetime.timedelta(-999999999)
Reread the manual: 1. "min" is minIMUM, not minUTES 2. You need: >>> diff.days 0 >>> diff.seconds 52662 >>> diff.microseconds 922000 >>> minutes = (diff.seconds + diff.microseconds / 1000000.0) / 60.0 >>> minutes 877.71536666666668 >>> > > > which is not good for me. > > So I tried to use toordinal like this > diff=b.toordinal()-a.toordinal() > > but I get > diff=1 > > Why? because toordinal() works only on the date part, ignoring the time part. HTH, John -- http://mail.python.org/mailman/listinfo/python-list
