John Machin wrote: > Lad wrote: > > Sybren Stuvel wrote: > > > Lad enlightened us with: > > > > How can I find days and minutes difference between two datetime > > > > objects? > > > > For example If I have > > > > b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000) > > > > a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000) > > > > > > diff = b - a > > > > Ok, I tried > > > > >>> diff=b-a > > >>> diff > > datetime.timedelta(0, 52662, 922000) > > >>> diff.min > > datetime.timedelta(-999999999) > > Reread the manual: > > 1. "min" is minIMUM, not minUTES > > 2. You need: > >>> diff.days > 0 > >>> diff.seconds > 52662 > >>> diff.microseconds > 922000 > >>> minutes = (diff.seconds + diff.microseconds / 1000000.0) / 60.0 > >>> minutes > 877.71536666666668 > >>> > > > > > > which is not good for me. > > > > So I tried to use toordinal like this > > diff=b.toordinal()-a.toordinal() > > > > but I get > > diff=1 > > > > Why? > > because toordinal() works only on the date part, ignoring the time > part. > > HTH, > John Thank you for the explanation
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