Tim Chase wrote: > >>> import re > >>> s ='a (b c) d [e f g] h ia abcd(b c)xyz d [e f g] h i' > >>> r = re.compile(r'(?:\S*(?:\([^\)]*\)|\[[^\]]*\])\S*)|\S+') > >>> r.findall(s) > ['a', '(b c)', 'd', '[e f g]', 'h', 'ia', 'abcd(b c)xyz', 'd', > '[e f g]', 'h', 'i'] > [...] > However, the above monstrosity passes the tests I threw at > it.
but it can't pass this one: "(a c)b(c d) e" the above regex gives out ['(a c)b(c', 'd)', 'e'], but the correct one should be ['(a c)b(c d)', 'e'] -- http://mail.python.org/mailman/listinfo/python-list
