>> >>> r = re.compile(r'(?:\([^\)]*\)|\[[^\]]*\]|\S)+') >> >>> r.findall(s) >>['(a c)b(c d)', 'e'] > > Ah, it's exactly what I want! I thought the left and right > sides of "|" are equal, but it is not true.
In theory, they *should* be equal. I was baffled by the nonparity of the situation. You *should" be able to swap the two sides of the "|" and have it treated the same. Yet, when I tried it with the above regexp, putting the \S first, it seemed to choke and give different results. I'd love to know why. > Thank you and Simon for your kindly help! My pleasure. A nice diversion from swatting spammers and getting our network back up and running today. I had hoped to actually get something productive done (i.e. writing some python code) rather than putting out fires. Sigh. -tkc -- http://mail.python.org/mailman/listinfo/python-list
