re.findall('\([^\)]*\)|\[[^\]]*|\S+', s)
Qiangning Hong wrote:
> I've got some strings to split. They are main words, but some words
> are inside a pair of brackets and should be considered as one unit. I
> prefer to use re.split, but haven't written a working one after hours
> of work.
>
> Example:
>
> "a (b c) d [e f g] h i"
> should be splitted to
> ["a", "(b c)", "d", "[e f g]", "h", "i"]
>
> As speed is a factor to consider, it's best if there is a single line
> regular expression can handle this. I tried this but failed:
> re.split(r"(?![\(\[].*?)\s+(?!.*?[\)\]])", s). It work for "(a b) c"
> but not work "a (b c)" :(
>
> Any hint?
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