"Michael Yanowitz" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hello:
>
> Maybe I am missing something, but from what I've seen,
> it is not possible to overload functions in Python. That
> is I can't have a
> def func1 (int1, string1):
> and a
> def func1 (int1, int3, string1, string2):
> without the second func1 overwriting the first.
I am hard put to think of why you would want to do something like that in
real code. The 2nd-parameter type mismatch will make using code harder to
write and read without bugs. Why not just give the two
different-but-related functions two different-but-related, names? But if
you insist ..., here is the Python way...
def func1(int1, int3, string1=None, string2=None):
"doc short calling sequence"
if string1==None:
string1 = int3; del int3, string2
<proceed with first body>
else:
<proceed with second body>
or
def func1(int1, *args):
if len(args ==1):
string1 = args[0]; del args
<proceed with first body>
elif len(args ==3):
int3,string1,string2 = args; del args
<proceed with second body>
else: <raise error>
> However, operators can be overloaded.
In the sense that you can define classes with appropriate special methods.
You can also give two different classes methods named 'func1'.
> So can I define a new operator?
No.
Terry Jan Reedy
--
http://mail.python.org/mailman/listinfo/python-list
