2 solutions:
In [98]: bars = ["str", "foobaz", "barbaz", "foobar"]
In [99]: for bar in bars: ....: if 'bar' in bar and 'baz' in bar: ....: print bar ....: print bars.index(bar) ....: barbaz 2
In [100]: for i in range(len(bars)): .....: if 'bar' in bars[i] and 'baz' in bars[i]: .....: print bars[i] .....: print i .....: barbaz 2
The first one is slow and pretty, the second one is fast and (a bit) ugly. I believe that you should avoid range(len(x)) when you can, but use it when you need to know the index of something without an additional x.index() call.
See Mark's post, if you "need to know the index of something" this is the perfect case for enumerate (assuming you have at least Python 2.3):
py> bars = ["str", "foobaz", "barbaz", "foobar"] py> for i, bar in enumerate(bars): ... if 'bar' in bar and 'baz' in bar: ... print bar ... print i ... barbaz 2
The only time where I even consider using range(len(x)) is when I don't also need to look at the item -- which I find to be quite uncommon...
Steve -- http://mail.python.org/mailman/listinfo/python-list
