> On Wed, 19 Jan 2005 22:04:44 -0500, Bob Smith wrote:
> > [...] how to find an element's numeric value (0,1,2,3...)
> > in the list. Here's an example of what I'm doing:
> >
> > for bar in bars:
> > if 'str_1' in bar and 'str_2' in bar:
> > print bar
> >
> > This finds the right bar, but not its list position. The reason I
need
> > to find its value is so I can remove every element in the list
before it
> > so that the bar I found somewhere in the list becomes element 0...
does
> > that make sense?
I have borrowed the bars list example from
"Bill Mill"s solutions and here are
the two solutions...
bars = ['str', 'foobaz', 'barbaz', 'foobar']
# Solution 1: The enumerate().
for idx, bar in enumerate(bars):
if 'bar' in bar and 'baz' in bar:
break
bars_sliced = bars[idx:]
print bars_sliced
# Solution 2: Low level approach, testing and removing combined. In
situ.
while bars: # some prefer len(bars) > 0, which is less magical, IMHO
bar = bars.pop(0) # get and remove the first
element
if 'bar' in bar and 'baz' in bar:
bars.insert(0, bar) # insert the tested back
break # and finish
print bars
The result is ['barbaz', 'foobar'] in both cases.
Petr
--
Petr Prikryl (prikrylp at skil dot cz)
--
http://mail.python.org/mailman/listinfo/python-list
