Hi Andrea,
[EMAIL PROTECTED] wrote:
I was wondering if there is a faster/nicer method (than a for loop) that will allow me to find the elements (AND their indices) in a list that verify a certain condition. For example, assuming that I have a list like:
mylist = [0, 1, 1, 1, 1, 5, 6, 7, 8, 1, 10]
I would like to find the indices of the elements in the list that are equal to 1 (in this case, the 1,2,3,4,9 elements are equal to 1). I could easily use a for loop but I was wondering if there is a faster method...
you could use something like this:
>>> mylist = [0, 1, 1, 1, 1, 5, 6, 7, 8, 1, 10] >>> [x[0] for x in enumerate(mylist) if x[1] == 1] [1, 2, 3, 4, 9]
Greetings, Joachim
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