[EMAIL PROTECTED] wrote:
Hello NG,
I was wondering if there is a faster/nicer method (than a for loop)
that will allow me to find the elements (AND their indices) in a list that
verify a certain condition. For example, assuming that I have a list like:
mylist = [0, 1, 1, 1, 1, 5, 6, 7, 8, 1, 10]
I would like to find the indices of the elements in the list that are equal
to 1 (in this case, the 1,2,3,4,9 elements are equal to 1). I could easily
use a for loop but I was wondering if there is a faster method...
Thanks for every suggestion.
Andrea.
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You could do a list comprehension /generator expression. Like this:
[i for i in range(len(mylist)) if mylist[i] == 1]
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Ola Natvig <[EMAIL PROTECTED]>
infoSense AS / development
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