On Mon, 2004-12-06 at 10:01, Timothy Babytch wrote:
> Serhiy Storchaka wrote:
>
> >>>sum([['N', 'F'], ['E'], ['D']], [])
> ['N', 'F', 'E', 'D']
>
> THE BEST!
>
> --
> Timothy Babytch, PHP-dev Teamleader
Sum certainly takes the cake for hackish elegance, and would be my
choice if I was absolutely certain that my data structure was exactly a
list of lists. A more general solution with applicability to arbitrary
levels of nesting is below.
a = [['N','F'],['E'],['D']]
b = [[['A','B',['C','D']],'N','F'],'E', ['F'] ]
c = iter([[iter(['A','B',('C','D')]),'N','F'],'E', iter(['F']) ])
def flatten( i ):
try:
i = i.__iter__()
while 1:
j = flatten( i.next() )
try:
while 1:
yield j.next()
except StopIteration:
pass
except AttributeError:
yield i
if __name__ == "__main__":
print list( flatten( a ) )
print list( flatten( b ) )
print list( flatten( c ) )
Which when run gives you ...
['N', 'F', 'E', 'D']
['A', 'B', 'C', 'D', 'N', 'F', 'E', 'F']
['A', 'B', 'C', 'D', 'N', 'F', 'E', 'F']
Adam DePrince
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