Nick Coghlan wrote: > from itertools import chain > n = [['N', 'F'], ['E'], ['D']] > print [chain(*n)]
However, [generator] is not the same as list(generator): >>> from itertools import chain >>> n = [['N', 'F'], ['E'], ['D']] >>> print [chain(*n)] [<itertools.chain object at 0x402ac60c>] >>> print list(chain(*n)) ['N', 'F', 'E', 'D'] And with the star operator you are foregoing some laziness, usually an important selling point for the iterator approach. Therefore: >>> n = [['N', 'F'], ['E'], ['D']] >>> lazyItems = (x for y in n for x in y) >>> lazyItems.next() 'N' >>> list(lazyItems) ['F', 'E', 'D'] >>> Of course this makes most sense when you want to keep the original n anyway _and_ can be sure it will not be mutated while you are still drawing items from the lazyItems generator. Peter -- http://mail.python.org/mailman/listinfo/python-list
