My point, I guess, is that it is possible to quickly get a solution to a specific problem like this without being a total expert. The code below was typed out once, and with only one minor correction before it produced the required behaviour. Sure, it is not the general solution, but *this is WHY I use python* - You get a lot of mileage out of the basics. Plus, I can still read and understand the sub-optimal code, and probably will be able to several years from now :)
Regular expressions are real powerful, and I am learning through using ViM - but it takes time and practice.
(err, I didn't include your example with quotes, but you should get the general idea)
***
'>>> stngs = [r'This Is An $EXAMPLE String', r'This Is An $EXAMPLE.String', r'This Is An $EXAMPLE',r'This Is An \$EXAMPLE\String']
'>>> stngs
['This Is An $EXAMPLE String', 'This Is An $EXAMPLE.String', 'This Is An $EXAMPLE', 'This Is An \\$EXAMPLE\\String']
'>>> for i in stngs:
wdlist = i.split(' ')
for j in wdlist:
if j.find(r'$') > -1:
dwd = j.split('.')[0]
if dwd.find('\\') > -1:
dwd = dwd.split('\\')[1]
print dwd
$EXAMPLE
$EXAMPLE
$EXAMPLE
$EXAMPLE
'>>>
***
On Wed, 01 Dec 2004 13:40:17 +0100, Peter Otten <[EMAIL PROTECTED]> wrote:
[EMAIL PROTECTED] wrote:
identifying/extracting a substring from another string. What I have to do
is to extract all the strings that begins with a "$" character, but
excluding characters like "." (point) and "'" (single quote) and "\" "/"
(slashes). For example I have:
1) This Is An $EXAMPLE String 2) This Is An $EXAMPLE.String 3) 'This Is An $EXAMPLE' 4) This Is An \$EXAMPLE\String;
I would like to extract only the "keyword" $EXAMPLE and what I'm using at
Is that what you want?
import re r = re.compile("[$]\w+") r.findall("""... 1) This Is An $EXAMPLE String ... 2) This Is An $EXAMPLE.String ... 3) 'This Is An $EXAMPLE' ... 4) This Is An \$EXAMPLE\String; ... """) ['$EXAMPLE', '$EXAMPLE', '$EXAMPLE', '$EXAMPLE']
Peter
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