Gianni Mariani <gia...@mariani.ws> added the comment:
@Arjun - this is about default values (See the bug description - Using a
frozendict as a default value)
Try this:
from frozendict import frozendict
from dataclasses import dataclass
@dataclass
class A:
a: frozendict = frozendict(a=1)
This used to work until frozendict became a subclass of dict.
Perhaps another fix is to convert any dict to a frozendict? Maybe not.
How would you handle this case? The only thing I figured was:
from frozendict import frozendict, field
from dataclasses import dataclass
AD=frozendict(a=1)
@dataclass
class A:
a: frozendict = field(default_factory=lambda:AD)
Which imho is cumbersome.
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue44674>
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