Arjun <ccldar...@icloud.com> added the comment:
Which frozendict does your message concern? I found this in some test: https://github.com/python/cpython/blob/bb3e0c240bc60fe08d332ff5955d54197f79751c/Lib/test/test_builtin.py#L741 or are you suggesting any user defined immutable object? I'm not sure indicating that an object should be immutable to dataclasses will be less cumbersome than default_factory. Currently, you have to do this: > x: frozendict = field(default_factory=frozendict) But, indicating mutability would be something like this: > x: frozendict = field(mutable=false) ---------- nosy: +CCLDArjun _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue44674> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
