Martin v. Löwis added the comment:

I think you are misinterpreting the grammar. Your code declares that U+00B2 
(SUPERSCRIPT TWO, ²) is an identifier character. Its category is No, so it is 
actually not. However, its normalization is U+0032 (DIGIT TWO, 2), which is an 
identifier character - but that doesn't make SUPERSCRIPT TWO a member of 
XID_Continue.

----------

_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue21765>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe: 
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com

Reply via email to