Martin v. Löwis added the comment:
Tal: If you want to verify your is_id_char function, you could use the code
for i in range(65536):
c = chr(i)
c2 = 'a'+c
if is_id_char(c) != c2.isidentifier():
print('\\u%.4x'%i,is_id_char(c),c2.isidentifier())
Alternatively, you could use the strategy taken in that code for is_id_char
itself:
def is_id_char(c):
return ('a'+c).isidentifier()
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue21765>
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