Antoine Pitrou added the comment: Anton, the test is wrong: it is taking a reference to the iterable object (the list), not the iterator.
To check the reference to the original iterator is released, something like this would work: >>> import itertools, weakref >>> it = (x for x in (1, 2)) >>> wr = weakref.ref(it) >>> it = itertools.islice(it, 1) >>> wr() is None False >>> list(it) [1] >>> wr() is None # returns True with the patch, False without True ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue21321> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
