end up I just use a simple array to solve the issue:
Examples
<https://docs.puppetlabs.com/puppet/latest/reference/lang_iteration.html#examples>Declaring
Resources
<https://docs.puppetlabs.com/puppet/latest/reference/lang_iteration.html#declaring-resources>
Since the focus of the Puppet language is declaring resources, most people
will want to use iteration to declare many similar resources at once:
$binaries = ["cfacter", "facter", "hiera", "mco", "puppet", "puppetserver"]
# function call with lambda:$binaries.each |String $binary| {
file {"/usr/bin/$binary":
ensure => link,
target => "/opt/puppetlabs/bin/$binary",
}}
On Tuesday, October 20, 2015 at 5:23:13 PM UTC-7, yi zhao wrote:
>
> Hi,
> so we have a few template setup under my_module/templates/
> like
> create_pre_rac_setup.sh.erb
> run_this_rac.sh.erb
> ....
>
>
> and I write someting in init.pp
>
> $db_setup_home = "$dbnamehome/dbs/create_$dbname"
> file { "$db_setup_home/create_pre_rac_setup_$dbname.sh":
> ensure => 'file',
> content => template("${module_name}/create_pre_rac_setup.sh.erb"),
> mode => '0644',
> owner => 1001,
> group => 1000,
> }
>
> file { "$db_setup_home/run_this_rac_$dbname.sh":
> ensure => 'file',
> content => template("${module_name}/run_this_rac.sh.erb"),
> mode => '0644',
> owner => 1001,
> group => 1000,
> }
>
> but if I have 500 templates, I would have to write 500 files which is
> against puppet thinking, is there a way to write a loop to read all
> template files under my_module/templates/
> then just loop to create the files with the same naming standard?
>
>
> thank you.
>
>
>
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