On Tue, 2011-12-13 at 10:31 -0800, Kenneth Lo wrote:
> Searching old archive I find this topic:
>
> http://groups.google.com/group/puppet-users/browse_thread/thread/187ee3897a26ae2a/32fea612e79dda80?hl=en&lnk=gst&q=puppet+case+statement+in+file+resource#32fea612e79dda80
>
>
> I understand that "case statements must be outside of resource
> statements" per that discussion and I understand the usage for the
> selector in-statement solution, however that's just for assignment
> though.
>
> Consider this simple file resource, I just want to have a external
> variable that control whether I need the file in the system:
>
> file { "somefile" :
>
> case ${hasfile} {
> "true": { ensure => present }
> default: { ensure => absent }
> }
> source => "puppet:///somefile",
> owner => "root",
> .
> .
> .
> }
>
>
> Obviously I had a syntax error here because case statement is not
> happy within the resource.
That's why the documentation says to use a selector.
> So, what's a recommended puppet way to do something like this? thx in
> advance.
file {
"somefile" :
ensure => $hasfile ? {
"true" => present,
default => absent
},
source => "puppet:///somefile",
owner => "root",
}
Please note that "true" is not strictly equivalent to the bareword true
in the puppet language :)
--
Brice Figureau
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