Le 23/12/2012 15:28, Robert Moskowitz a écrit :
>
> On 12/23/2012 09:20 AM, Noel Jones wrote:
>> On 12/23/2012 7:17 AM, Robert Moskowitz wrote:
>>>> You can chase these with something like:
>>>>
>>>> # postconf -n | while read parameter equal value; do
>>>> default_value=`postconf -d $parameter 2>&1`;
>>>> if [ "$value" = "$default_value" ]; then
>>>> echo "NOTICE: Useless setting: $parameter = $value";
>>>> fi;
>>>> done
>>>>
>>> I have been running this against the base Centos 6 install that has
>>> a main.cf with lots of comments and a few parameter lines.
>>>
>>> postconf -n shows about 20 parameters, and when I compare these
>>> against postconf -d only 9 of them are different.
>> That sounds about right. A basic postfix install needs only a few
>> non-default settings.
>>
>>
>>> parameters like mailq_path is now /usr/bin/mailq.postfix and the
>>> default is /usr/bin/mailq
>> sounds reasonable.
>>
>>> I look at the script and I am not able to tell what is wrong; can
>>> you help me get it right? I think this is a real useful tool.
>> It's unclear what problem you are having. Please explain.
>
> When I run the script shown above, there is no output. Yet I know
> there are lines in the main.cf that differ from the defaults.
> That is there are 9 lines shown in the -n option that are different
> from shown in the -d option. I would think that the above script
> should have printed those lines.
No. the only output of the script is the one in the 'echo' line: it only
prints anything if the value is the same in main.cf and in `postconf
-d`. To see local settings, use 'postconf -n'. that's its job.
If you really insist, here is a modified version of the script:
postconf -n | while read parameter equal value; do
default_value=`postconf -d $parameter 2>&1`;
if [ "$value" = "$default_value" ]; then
echo "NOTICE: Useless setting: $parameter = $value";
else
echo "$parameter = $value"
fi;
done
but this is too complex for the task.
>
> I ran the script both as me and as root.
>
