Add up the total power the PSU can generate, using P = IV

Determine I (current) on each voltage rail (V), it's printed on the PSU.

e.g. 30A @ 3.3V = 99W
15A @ 5V = 75W

etc. and add them all up. This is the PSU's total power output. The
PSU will also have a plaque at the back which gives its power
consumption, something like 220V, 2A. This comes out to 440
Volt-Amperes (which is different from Watts). You can assume a 0.707
conversion from V-A to Watts. Then divide the total output power, by
the power consumed ( Volt-Amperes * 0.707 ) to get the efficiency.

That said, switch-mode power supply technology is a mature, stable
science. So you won't see any glaring differences from one power
supply to the next. The differentiator would be in things like build
quality, the use of high-quality inductors, etc. But on paper they
will all look the same.


On 7/31/07, [C]hicken [G] od <[EMAIL PROTECTED]> wrote:
> With all this talk about PSU efficiency, how does one determine or measure
> the efficiency of a PSU. I'm scouting the market for a new box, myself.
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