Do this: <?php if (@!isset($test)) echo "test does not exist"; ?>
The @ turns off error reporting for that function. -Dash -----Original Message----- From: F.Anneveld [mailto:[EMAIL PROTECTED]] Sent: Monday, November 18, 2002 7:58 AM To: [EMAIL PROTECTED] Subject: [PHP-WIN] PHP variable Hello, When I use the following code my browser comes with the following error : -------------------------------------------------------------------- PHP code: <?php if (!$test) echo "test does not exist"; ?> -------------------------------------------------------------------- Browser error: Notice: Undefined variable: test in d:\www\trash.php on line 3 test does not exist -------------------------------------------------------------------- But in PHP you don't have to declare a variable or do I have to ajust some setting in the PHP.ini ???? Thank you, Frank -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php