if (!isset($test)) echo "test does not exist";
-- Best regards, George Nicolae IT Manager ___________________ PaginiWeb.com - Professional Web Design www.PaginiWeb.com "F.Anneveld" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Hello, > > When I use the following code my browser comes with the following error : > -------------------------------------------------------------------- > PHP code: > > <?php > if (!$test) echo "test does not exist"; > ?> > -------------------------------------------------------------------- > Browser error: > > Notice: Undefined variable: test in d:\www\trash.php on line 3 > test does not exist > > -------------------------------------------------------------------- > But in PHP you don't have to declare a variable > or do I have to ajust some setting in the PHP.ini ???? > > > Thank you, > > Frank > > -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php