it's a browser thing, i guess, when you use an image as a submit button

Martin

-----Original Message-----
From: jtjohnston [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 28, 2002 4:28 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] if(isset($submit))


I s'pose, but where/why are you getting submit.x=118&submit.y=20

Martin Towell wrote:

> I used this code
>
> <form action="/inetpub/wwwroot/top.html" method="get">
> <input type="image" src="none.gif" width="125" height="25" name="submit"
> value="submit">
> </form>
>
> when I clicked on the image, I got this url
>
> file:///C:/inetpub/wwwroot/top.html?submit.x=118&submit.y=20
>
> so php would get this as $submit_x and $submit_y
>
> HTH
> Martin
>
> -----Original Message-----
> From: jtjohnston [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, February 28, 2002 4:17 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] if(isset($submit))
>
> Has anyone tried:
>
> <input type=\"image\"  name=\"submit\" value=\"submit\"
> src=\"next.gif\" border=\"0\" align=\"ABSCENTER\">
>
> instead of :
>
> <input type=\"submit\" name=\"submit\" value=\">>\">
>
> I can't get this to work:
> if(isset($submit))
>
> with:
>
> <input type=\"image\"  name=\"submit\" value=\"submit\"
> src=\"next.gif\" border=\"0\" align=\"ABSCENTER\">
>
> I'm not coding correctly?
>
> --
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--
John Taylor-Johnston
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