I used this code <form action="/inetpub/wwwroot/top.html" method="get"> <input type="image" src="none.gif" width="125" height="25" name="submit" value="submit"> </form>
when I clicked on the image, I got this url file:///C:/inetpub/wwwroot/top.html?submit.x=118&submit.y=20 so php would get this as $submit_x and $submit_y HTH Martin -----Original Message----- From: jtjohnston [mailto:[EMAIL PROTECTED]] Sent: Thursday, February 28, 2002 4:17 PM To: [EMAIL PROTECTED] Subject: [PHP] if(isset($submit)) Has anyone tried: <input type=\"image\" name=\"submit\" value=\"submit\" src=\"next.gif\" border=\"0\" align=\"ABSCENTER\"> instead of : <input type=\"submit\" name=\"submit\" value=\">>\"> I can't get this to work: if(isset($submit)) with: <input type=\"image\" name=\"submit\" value=\"submit\" src=\"next.gif\" border=\"0\" align=\"ABSCENTER\"> I'm not coding correctly? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
