array_search returns the key-value of the searched value that is found... in
the first case... the returned key is 0.... because it's the first
element... however... 0 is also the same as FALSE...
you should use === (three ='s) ... it's used to compare both value and
type... (and 0 is not the same type as FALSE)...
Greets,
Edward
----- Original Message -----
From: "Roger Keays" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 26, 2002 10:29 AM
Subject: [PHP] array_search
> Hi,
>
> Can anybody explain why the output of this script is
>
> not found
> Found!
>
> Here is the script...
>
> $legalfields = array("reasonForRepair");
> if (array_search("reasonForRepair", $legalfields) == TRUE) {
> echo "Found!<br>";
> } else {
> echo "not found<br>";
> }
> $legalfields = array("foo", "reasonForRepair");
> if (array_search("reasonForRepair", $legalfields) == TRUE) {
> echo "Found!";
> } else {
> echo "not found";
> }
> ?>
>
> Thanks in advance,
>
> Roger
>
>
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