On Tue, 2002-02-26 at 01:29, Roger Keays wrote: > Hi, > > Can anybody explain why the output of this script is > > not found > Found!
Yup. array_search() returns the key of the found object, as noted in the docs (http://www.php.net/array_search). Since the first test has the searched-for field at index 0, array_search() will return an int. You're doing a loose (==) test against TRUE (a boolean, not an int), so you get 'not found.'. In the second example, the searched-for item is at index 1, which does loosely evaluate to TRUE. I think the function you're looking for is in_array(): http://www.php.net/in_array Cheers, Torben > Here is the script... > > $legalfields = array("reasonForRepair"); > if (array_search("reasonForRepair", $legalfields) == TRUE) { > echo "Found!<br>"; > } else { > echo "not found<br>"; > } > $legalfields = array("foo", "reasonForRepair"); > if (array_search("reasonForRepair", $legalfields) == TRUE) { > echo "Found!"; > } else { > echo "not found"; > } > ?> > > Thanks in advance, > > Roger > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- Torben Wilson <[EMAIL PROTECTED]> http://www.thebuttlesschaps.com http://www.hybrid17.com http://www.inflatableeye.com +1.604.709.0506 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
