On Wed, 2010-10-20 at 20:11 -0400, Bastien wrote:
>
> On 2010-10-20, at 7:59 PM, David McGlone <da...@dmcentral.net> wrote:
>
> > Hi everyone, it's me again :-/
> >
> > I'm having a whole lot of trouble figuring out how to return a result
> > from a query such as in this code example:
> >
> > function LearnIt(){
> > $query = "SELECT learn_id FROM mydatabase ";
> > $result = mysql_query($query);
> > return $result;
> > }
> >
> > I already achieved a connection to the database with no problem, to
> > verify I wrote this query also:
> >
> > function GetMeARow(){
> >
> > $query = "SELECT learn_id FROM mydatabase ";
> > $result = mysql_query($query);
> > while($row = mysql_fetch_array($result)){
> > echo $row[learn_id];
> > }
> >
> > With the latter, It works as expected, echoing the 2 rows I have in the
> > DB, but I'm trying to understand the method used in the former.
> >
>
>
> David, the $result variable/object is the handle to the result data set,
> not the resulting data. You would still need to access the data set via
> the Mysql_* set of functions like Mysql-fetch_array or Mysql_result like
> you did in the second example
HaHa! How burnt out does one have to be to overlook this a million times
and still not get it?
Thanks I see now :-)
--
Blessings
David M.
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