On 2010-10-20, at 7:59 PM, David McGlone <da...@dmcentral.net> wrote:
> Hi everyone, it's me again :-/
>
> I'm having a whole lot of trouble figuring out how to return a result
> from a query such as in this code example:
>
> function LearnIt(){
> $query = "SELECT learn_id FROM mydatabase ";
> $result = mysql_query($query);
> return $result;
> }
>
> I already achieved a connection to the database with no problem, to
> verify I wrote this query also:
>
> function GetMeARow(){
>
> $query = "SELECT learn_id FROM mydatabase ";
> $result = mysql_query($query);
> while($row = mysql_fetch_array($result)){
> echo $row[learn_id];
> }
>
> With the latter, It works as expected, echoing the 2 rows I have in the
> DB, but I'm trying to understand the method used in the former.
>
> --
> Blessings
> David M.
>
>
>
>
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David, the $result variable/object is the handle to the result data set, not
the resulting data. You would still need to access the data set via the Mysql_*
set of functions like Mysql-fetch_array or Mysql_result like you did in the
second example
Bastien Koert
>
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