Why would you do such strange things? It's a lot more simple :P
$now = time();
$plus7 = $now+(7*24*60*60); // 7 days, containing 24 hours each, containing 60 minutes each, containing 60 seconds each.
echo 'Current Date: '.date('Y-m-d', $now);
echo 'Date in 7 days: '.date('Y-m-d', $plus7);now isn't that easier ;)
Trevor Gryffyn wrote:
I disagree on the strtotime recommendations that everyone else gave. The mktime() function itself will compensate for leap years, "day = 36" type stuff and all of that.
<?php $curdate = date("Y-m-d"); $plus7 = date("Y-m-d",mktime(0,0,0,date("m"),date("d")+7,date("Y"))); Echo "Current Date: $curdate<br>"; Echo "+7 Dats Date: $plus7"; ?>
Simple as that!
-TG
-----Original Message-----
From: Louie Miranda [mailto:[EMAIL PROTECTED] Sent: Tuesday, July 27, 2004 11:31 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Adding +7 more days on date() value problem
I can't figure how could i add +7 more days on the DD (Day) value. My problem is, when the day is close on the end of the month like
07/29/2004
when i add +7 on 29 = 36, its obvious we dont have 36 on the calendar. And im creating a program below, to explode it and maybe just add +. But i think its useless if im just going to do + on the DD (Day) value.
Hmm :?
## <?php $curdate = date("Y-m-d"); $plus7 = explode("-", $curdate);
print (" <p>cut: " .$plus7[0]. " " .$plus7[1]. " " .$plus7[2]. " </p>
Current Date: $curdate<br> +7 Dats Date: $plus7
"); ?> ##
-- Louie Miranda http://www.axishift.com
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