I disagree on the strtotime recommendations that everyone else gave.
The mktime() function itself will compensate for leap years, "day = 36"
type stuff and all of that.

<?php
$curdate = date("Y-m-d");
$plus7 = date("Y-m-d",mktime(0,0,0,date("m"),date("d")+7,date("Y")));
Echo "Current Date: $curdate<br>";
Echo "+7 Dats Date: $plus7";
?>


Simple as that!

-TG

> -----Original Message-----
> From: Louie Miranda [mailto:[EMAIL PROTECTED] 
> Sent: Tuesday, July 27, 2004 11:31 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Adding +7 more days on date() value problem
> 
> 
> I can't figure how could i add +7 more days on the DD (Day) value. My
> problem is, when the day is close on the end of the month like
> 
> 07/29/2004
> 
> when i add +7 on 29 = 36, its obvious we dont have 36 on the calendar.
> And im creating a program below, to explode it and maybe just add +.
> But i think its useless if im just going to do + on the DD (Day)
> value.
> 
> Hmm :?
> 
> ##
> <?php
> $curdate = date("Y-m-d");
> $plus7 = explode("-", $curdate);
> 
> print ("
> <p>cut:
> " .$plus7[0]. "
> " .$plus7[1]. "
> " .$plus7[2]. "
> </p>
> 
> Current Date: $curdate<br>
> +7 Dats Date: $plus7
> 
> ");
> ?>
> ##
> 
> -- 
> Louie Miranda
> http://www.axishift.com
> 
> -- 
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 
> 

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