> print out all the values of the vars your comparing.... often youll > find one of them is not what your expecting > > Jason > > On Sat, 24 Jul 2004 11:05:06 -0500, Robb Kerr > <[EMAIL PROTECTED]> wrote: >> What's wrong with this syntax. I just can't see my mistake. >> >> if ($vBkgrndImage == "AnswerPage") { >> if ($vAnswerID_RS_PageContent != $row_RS_PageContent['CorrectAnswer']) >> { >> $vBkgrndImage = "Bkgrnd-Body-Incorrect.jpg"; >> } else { >> $vBkgrndImage = "Bkgrnd-Body-Correct.jpg"; >> } >> } >> >> Thanx >> -- >> Robb Kerr
Yes, see what the vars are, maybe something like this: if ($vBkgrndImage == "AnswerPage") { echo "1: $vAnswerID_RS_PageContent<br>"; echo "2:".$row_RS_PageContent['CorrectAnswer']."<br>"; } Then look on your page for the numbers 1 and 2 and see if the vars are what you're expecting. -- --Matthew Sims --<http://killermookie.org> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php