On Sat, 24 Jul 2004 18:18:23 +0200, Marek Kilimajer wrote:
> Robb Kerr wrote:
>> On Sat, 24 Jul 2004 12:09:41 -0400, Scot L. Harris wrote:
>>
>>
>>>On Sat, 2004-07-24 at 12:05, Robb Kerr wrote:
>>>
>>>>What's wrong with this syntax. I just can't see my mistake.
>>>>
>>>>if ($vBkgrndImage == "AnswerPage") {
>>>> if ($vAnswerID_RS_PageContent != $row_RS_PageContent['CorrectAnswer']) {
>>>> $vBkgrndImage = "Bkgrnd-Body-Incorrect.jpg";
>>>> } else {
>>>> $vBkgrndImage = "Bkgrnd-Body-Correct.jpg";
>>>> }
>>>>}
>>>>
>>>>Thanx
>>>
>>>Single quotes around CorrectAnswer?
>>>
>>>What is the error you are getting?
>>>
>>>Guessing that if it passes the syntax checks I expect your problem is it
>>>is always evaluating to one of the options and not the other.
>>
>>
>> You've got it. Syntax passes checking - always returns..
>> $vBkgrndImage = "Bkgrnd-Body-Correct.jpg"
>>
>> Single quotes around 'CorectAnswer' is because that entry is in the style
>> of table_recordset['field']. How else should this be coded?
>>
>> Thanx
>
> I think all column names are returned lowercased, so use
> $row_RS_PageContent['correctanswer']
Nope. That just changed the return to always be the other option.
--
Robb Kerr
Digital IGUANA
Helping Digital Artists Achieve their Dreams
----------------------------------------------------
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