Re: [PHP] Print a variable's name

[Ahbaid Gaffoor]

Thanks Ryan,
but what I want is to be able to pass any variable to a procedure and 
have the variable name and value printed by the procedure.

Can this be done?
I'm trying to extend my library of debugging functions/procedures by 
having a procedure which can be used to "inspect" a variable whenever I 
call it.

Thanks
Ahbaid
Ryan A wrote:
Just escape it...
eg:
$ryan = "something";
echo "\$ryan =".$ryan;
that would print:
$ryan = something
HTH.
Cheers,
-Ryan

On 5/5/2004 5:02:25 PM, [EMAIL PROTECTED] wrote:
 

I'd like to print a variable's name in a procedure along with it's
   

value....
 

Is there a way to do this?
for example:
--------------------------------------------------------------------------
   

-
 

function showvar($somevar) {
echo "Now showing: ". <....... code to show var name .....> ."\n";
echo "Value: ".$somevar;
}
$s1 = "Hello World";
showvar($s1);
--------------------------------------------------------------------------
   

-
 

would produce:
--------------------------------------------------------------------------
   

-
 

Now showing: $s1
Value: Hello World
--------------------------------------------------------------------------
   

-
 

many thanks in advance...
Ahbaid
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