Just escape it... eg:
$ryan = "something"; echo "\$ryan =".$ryan; that would print: $ryan = something HTH. Cheers, -Ryan On 5/5/2004 5:02:25 PM, [EMAIL PROTECTED] wrote: > I'd like to print a variable's name in a procedure along with it's value.... > > Is there a way to do this? > > > for example: > -------------------------------------------------------------------------- - > function showvar($somevar) { > > echo "Now showing: ". <....... code to show var name .....> ."\n"; > echo "Value: ".$somevar; > > } > > $s1 = "Hello World"; > showvar($s1); > -------------------------------------------------------------------------- - > > would produce: > -------------------------------------------------------------------------- - > Now showing: $s1 > Value: Hello World > -------------------------------------------------------------------------- - > > > many thanks in advance... > Ahbaid > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php