Hi Justin, Most Xcellent. Thanks alot!!!
Shew "J Morton" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Sorry I had a parentheses out of place, it should have been: > > <? > $this_date = "1/1/2003"; > > for($i=1; $i<=365; $i++) { > if (date("l", strtotime($this_date)) == "Friday") { > echo $this_date . "<br>"; > } > > $this_date = date("n/j/Y",mktime(0,0,0,date("m", > strtotime($this_date)),date("d", strtotime($this_date))+1,date("Y", > strtotime($this_date)))); > } > ?> > > Hope this helps, > Justin > > Shew wrote: > > > Hi, > > > > I'm trying to find a formula for displaying the date for every Friday of a > > given year, i.e. 2003 > > > > Jan 3, 2003 > > Jan 10, 2003 > > Jan 17, 2003 > > etc. > > > > Any ideas? > > > > Thanks > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
