How about something similar, but look for the first Friday and then add seven days (or 604800 seconds) to get the date of the next Friday?
-----Original Message----- From: J Morton [mailto:[EMAIL PROTECTED] Sent: Friday, 3 October 2003 11:20 AM To: Shew; [EMAIL PROTECTED] Subject: Re: [PHP] date brain teaser Sure -- <? $this_date = "1/1/2003"; for($i=1; $i<=365; $i++) { if (date("l", strtotime($this_date) == "Friday")) { echo $this_date . "<br>"; } $this_date = date("n/j/Y",mktime(0,0,0,date("m", strtotime($this_date)),date("d", strtotime($this_date))+1,date("Y", strtotime($this_date)))); } ?> Shew wrote: > Hi, > > I'm trying to find a formula for displaying the date for every Friday of a > given year, i.e. 2003 > > Jan 3, 2003 > Jan 10, 2003 > Jan 17, 2003 > etc. > > Any ideas? > > Thanks > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php __________ Information from NOD32 1.518 (20030925) __________ This message was checked by NOD32 for Exchange e-mail monitor. http://www.nod32.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
