""Ney andré de mello zunino"" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Thanks for the quick response, but I am not sure I understand your > argument. Yes, I am aware that the function returns an array > corresponding to a single row/record; what I don't understand is why I > am not able to apply a key directly to that "temporary" return value. In > other words, it is necessary to "copy" the resulting row into a new > variable so that it is then possible to use the column name (key) to > retrieve the desired value. Why don't you use :
<?php list ($fooVar) = mysql_fetch_row(mysql_query("SELECT barColumn FROM table_name WHERE id = 1")); ?> This will do exactly what you need, if I understand you correctly. HTH, -- Ivo Fokkema PHP & MySQL programmer Leiden University Medical Centre Netherlands -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php