[PHP] The return of mysql_fetch_assoc()

[Ney André de Mello Zunino]

Hello.

I wonder why the following code is not accepted by the PHP interpreter

$fooVar = mysql_fetch_assoc($result)["barColumn"];

I am forced to create an intermediary variable for the array returned 
from mysql_fetch_assoc(), like this:

$record = mysql_fetch_assoc($result);
$fooVar = $record["barColumn"];
Why is that? It doesn't seem logical. Could it be a bug?

Thank you,

--
Ney André de Mello Zunino
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