on top of your script add
extract ($_POST);
or may be a little more checking to see if its actually a form submission by
POST method like
if ($_SERVER["REQUEST_METHOD"] == 'POST')
extract($_POST);
same thing goes for GET
Then you can access all form variables just as you were accessing.
HTH
R'twick
"ØYstein HåLand" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> I'm not sure what you mean. To give ONE example:
> Earlier I could use this code on top of every page:
> if ($printout != "yeah") { include("header.php"); }
> This code gives an error today. The variable $printout is set if the
visitor
> choose to click on the 'print_page_image', otherwise the variable has no
> value.
>
> "Esteban FernáNdez" <[EMAIL PROTECTED]> skrev i meddelandet
> news:[EMAIL PROTECTED]
> > When you recivied that error ?, in a form ?, if is in a Form just put in
> the
> > top of .php files this code
> >
> > $HTTP_GET_VARS["variable2"];
> > $HTTP_GET_VARS["variable3"];
> >
> > Of course if you send with other method (post) change the GET for POST
> >
> > $HTTP_POS_VARS["variable2"];
> > $HTTP_POS_VARS["variable3"];
> >
> > Regards.
> >
> > Esteban.
> >
> >
> >
> > "ØYstein HåLand" <[EMAIL PROTECTED]> escribió en el mensaje
> > news:[EMAIL PROTECTED]
> > > None of my old scripts worx nowadays and the most common error message
> is
> > > 'undefined variable'. What is the best/simplest way to work around
this
> > > situation?
> > > if !isset($myvar) {
> > > do this
> > > blah blah
> > > }
> > > ?
> > >
> > >
> >
> >
>
>
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